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TN Maths, 11th, All Important Questions

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Welcome To Class : XI Subject : Maths IMPORTANT QUESTIONS Unit Wise Chapter 01 Chapter 07 Click Here Click Here Chapter 02 Chapter 08 Click Here Click Here Chapter 03 Chapter 09 Click Here ...

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TN 11th, Maths Chapter 2, Exercise 2.2

Welcome To Class : XI Subject : Maths Chapter : 2 Exercise : 2.2 Que 1 : Solve for " x " (i) |3-x| < 7 |x| < r -r < x < r |3-x|<7 -7 < (3-x) < 7 -7-3 < -x < 7-3 -10 < -x < 4 ∴ -4 < x < 10 (ii) |4x-5| ≥ -2 |x-a| ≥ r (x-a) ≥ -r |4x-5| ≥ 2 ∵ r < 0 x ∈ R (iii) |3-(3/4)x| ≤ 1/4 |3-(3/4)x| ≤ 1/4 3|1-(1/4)x| ≤ 1/4 |1-(1/4)x| ≤ 1/12 |(4-x)/4| ≤ 1/12 1/4|4-x)| ≤ 1/12 |4-x| ≤ (1/12)(4/1) |4-x| ≤ 1/3 [-(x-4)] ≤ 1/3 |x-a|≤ r -1/3 ≤ x-4 ≤ 1/3 -r ≤ x-a ≤ r (-1/3)+(4) ≤ x ≤ (1/3)+(4) 11/3 ≤ x ≤ 13/3 (iv) |x|-10 < -3 |x|<7 -r < x < r |x|-10 < -3 |x| < -3+10 |x| < 7 -7 < x < 7 Que 2 : Solve (1/|2x-1|) < 6 and express the solution using the interval notation. Solution : (1/|2x-1|) < 6...

TN 11th, Maths

Welcome To Class : XI Subject : Maths 11th Maths Text Book Volume 1 Click Here Volume 2 Click Here Chapter 1 Exercise 1.1 Click Here Exercise 1.2 Click Here Exercise 1.3 Click Here Exercise 1.4 Click Here Thank You For Refering On Our Page

TN Maths, 11th, All Important Questions

Welcome To Class : XI Subject : Maths IMPORTANT QUESTIONS Unit Wise Chapter 01 Chapter 07 Click Here Click Here Chapter 02 Chapter 08 Click Here Click Here Chapter 03 Chapter 09 Click Here ...

TN 11th, Maths Chapter 1, Exercise 1.3

Welcome To Class : XI Subject : Maths Chapter : 1 Exercise : 1.3 Que 1 : Suppose that 120 students are studying in 4 sections of eleventh standard in a school. Let A denote the set of students and B denote the set of the sections. Define a relation from A to B as “x related toy if the student x belongs to the section y”. Is this relation a function? What can you say about the inverse relation? Explain your answer. Solution : A = {set of students in 11th standard} B = {set of sections in 11th standard} R : A ➝ B ⇒ x related to y ⇒ Every students in eleventh Standard must in one section of the eleventh standard. ⇒ It is a function. Inverse relation cannot be a function since every section of eleventh standard cannot be related to one student in eleventh standard. Que 2 : Write the values of f at – 4, 1, -2, 7, 0 if Solution : f(-4) = -(-4) + 4 = 4+4 = 8 f(1) = 1 – 1² = 0 f(-2) = (-2)² ...

TN Physics, 12th All Important Questions

Welcome To Class : XII Subject : Physics IMPORTANT QUESTIONS By Unit Wise Unit - 1 Unit - 6 Click Here Click Here Unit - 2 Unit - 7 Click Here Click Here Unit - 3 Unit - 8 Click Here Click Here Unit - 4 Unit - 9 Click Here ...

TN 11th, Maths Chapter 1, Exercise 1.4

Welcome To Class : XI Subject : Maths Chapter : 1 Exercise : 1.4 Que 1 : For the curve y = x³ given in Figure, draw (i) y = -x³ (ii) y = x³ + 1 (iii) y = x³–1 (iv) y = (x + 1)³, with the same scale. Solution : (i) y = -x³ y=-f(x) It is the reflection of the graph of f About the x-axis (ii) y = x³ + 1 The graph of y = f(x) + 1 is shifted upward to 1 unit. (iii) y = x³ – 1 The graph of y = x³ – 1 is shifted downward to 1 unit (iv) y = (x + 1)³ The graph of y = (x + 1)³ is shifted to the left for 1 unit. Que 2 : For the curve, y = (x^⅓) given in figure draw. (i) y = (-x^⅓) (ii) y=(x^⅓) +1 (iii) y= (x^⅓) -1 (iv) y=(x+1)^⅓ Solution : (i) y = (- x)^⅓ Then y = -x^⅓ is the reflection of the graph of y=x^⅓ about the x-axis. (ii) y=(x^⅓) +1 Then y= (x^⅓)+1 is the x graph of y = x^⅓ shifts to the upwards for one unit. (iii) y= (x^...

TN 11th, Maths Chapter 1, Exercise 1.1

Welcome To Class : XI Subject : Maths Chapter : 1 Exercise : 1.1 Que 1 : Write the following in roster form: (i) {x ∈ N : x² < 121 and x is a prime}; Solution : x is a Prime Number; x² < 121 Let 2² = 4, 3² = 9 , 5² = 25, 7² = 49, (i.e) x²<121 So We Take 2,3,5,7 A = {2, 3, 5, 7} (ii) The set of all positive roots of the equation (x – 1)(x + 1)(x2 – 1) = 0; Solution : Let x-1= 0; x+1 = 0; x²+1 = 0 x = 1; x = -1; x = ±1 Let "B" as the the set of all positive roots of the equation (x – 1)(x + 1)(x2 – 1) B = { 1, -1, ±1} Only Positive Roots So We Take B = {1} B = {1} (iii) {x ∈ N : 4x + 9 < 52}; Solution : 4x + 9 < 52 Add (-9) On Both Side 4x + 9 – 9 < 52 – 9 ...

TN Maths, 12th All Important Questions

Welcome To Class : XII Subject : Maths IMPORTANT QUESTIONS Chapter 02 Chapter 07 Click Here Click Here Chapter 03 Chapter 08 Click Here Click Here Chapter 04 Chapter 09 Click Here ...

TN 11th, Maths Chapter 1, Exercise 1.2

Welcome To Class : XI Subject : Maths Chapter : 1 Exercise : 1.2 Que 1 : Discuss the following relations for reflexivity, symmetricity and transitivity: (i) The relation R defined on the set of all positive integers by “mRn if m divides n”. (ii) Let P denote the set of all straight lines in a plane. The relation R defined by “lRm if l is perpendicular to m”. (iii) Let A be the set consisting of all the members of a family. The relation R defined by “aRb if a is not a sister of b”. (iv) Let A be the set consisting of all the female members of a family. The relation R defined by “aRb if a is not a sister of b”. (v) On the set of natural numbers the relation R defined by “xRy if x + 2y = 1”. (i) Solution : S = {set of all positive integers} (a) mRm ⇒ ‘m’ divides’m’ ⇒ reflexive (b) mRn ⇒ m divides n but nRm ⇒ n does not divide m (i.e.,) mRn ≠ nRm It is not symmetric (c) mRn ⇒ nRr as n divides r It is transitive. (ii) Solution ...

Chapter 2, Question Paper

Welcome To Class : XI Subject : Maths Chapter : 2 Question Paper Mark : 50 Marks Section - A I . Choose The Correct Answer : (10×1=10) 1. The Value Of ⁴√(-2)⁴ = __________. a) 2 b -2) c) 4 d) -4 2. If |x-2|>5, then x belongs to a) (-∞,-2]∪[5,∞) b) (-∞,-3]∪[7,∞) c) (-∞,-3]∪[7,∞) d) (-∞,2]∪[5,∞) 3. For x≥2, |x-2| = a) 2-x b) 2+x c) x-2 d) x 4. The Value Of log 1 is a) 1 b) 0 c) ∞ d) -1 5. If Quadratic With Real Coefficient has no real roots, then it's discriminant is ________. a) 0 b) <0 c) >0 d) 1 6. If √(x+14)<2, then x belongs to a) [-14,-10) b) (-14,-10] c) (-∞,-10] d) [-14,-10) 7. Find Odd One Out Of The Fo...

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