TN 11th, Maths Chapter 2, Exercise 2.1
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Subject : Maths
Chapter : 2
Exercise : 2.1
Que 1 :
Classify each element of {√7,-¼,0,3.14,4,(22/7)} as a member of ℕ, Q, ℝ, -Q or ℤ.
Solution :
√7 irrational number
Q = R-Q
√7 ∈ R-Q
-¼ negative rational number
-¼ ∈ Q
0 Integer & Rational Number
0 ∈ Z,Q
3.14 Rational Number
3.14 ∈ Q
4 Natural Number, Rational Number
4 ∈ N, Z, Q
22/7 Rational Number
Que 2 :
Prove That √3 is an irrational number.
Solution :
Let Assume That
√3 is Rational Number
i.e √3 = (m/n); m,n ∈ z ; n ∈ 0
n√3 = m
Squaring on Both Side;
(n√3)² = m²
3n² = m² ------------------------------ (1)
Let m² is even
m must be even
m = 2k
Substitute
m = 2k in (1)
3n² = m²
3n² = 4k²
n² = (4k²/3)
n² & n also an even number
m and n have common factor 2
This Contradiction that m and n have no factor greater than one
∴ √3 is an irrational number.
Que 3 :
Are There Two Distinct irrational number, such that their difference is Rational Number. Justify.
Solution :
= (2+√2) - (1+√2)
= 2+√2-1-√2
= 2-1
= 1
1 Is an Rational Number
Que 4 :
Find 2 irrational Number Such That Their sum is a rational number, Can you find two irrational number, Whose product is a rational number.
Solution :
2+√2 ; 2-√2
Sum Of The Root
= (2+√2) + (2-√2)
= 2+2
= 4 ∈ Q
Product Of The Root
= (2+√2)(2-√2)
= 2²-(√2)²
= 4 - 2
= 2 ∈ Q
Que 5 :
Find the positive number Smaller than 1/2¹⁰⁰⁰. Justify.
Solution :
Given number is 1/2¹⁰⁰⁰
Let 1000<1001
∴ 2¹⁰⁰⁰ < 2¹⁰⁰¹
1/2¹⁰⁰⁰ < 1/2¹⁰⁰¹
∴ Positive Number is smaller than 1/2¹⁰⁰⁰ is 1/2¹⁰⁰¹
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